How much gravity can a 3mm thick welded tube withstand?
The calculation formula for the pressure that the welded pipe can withstand:
P=(2*σ/S*δ)/D
Among them: the pressure is P, the tensile strength is σ, S is the safety factor, the wall thickness is δ, and the outer diameter is D.
for example:
DN=10MM, wall thickness is 3mm, what is the maximum pressure of seamless steel welded pipe?
The tensile strength of the material is σ, the pressure is P, and the outer diameter is D;
Welded pipe wall thickness δ=(P*D)/(2*σ/S)
S is the safety factor;
Because P is less than 7 MPa, S selects S=8; P is less than 17.5 MPa, S selects S=6; P is greater than 17.5 MPa, and S selects S=4;
We choose the safety factor of S=6; the tensile strength of 20 steel is 410MPa.
Therefore, the pressure that the welded pipe can withstand
P=(2*σ/S*δ)/D
=(2*410/6*3)/(10+6)
=26.25MPa>Set 17.5MPa
Therefore, the safety factor is taken as S=4
Therefore, the pressure that the welded pipe can withstand P=(2*σ/S*δ)/D
=(2*410/4*3)/(10+6)
=39.375MPa
P=(2*σ/S*δ)/D
Among them: the pressure is P, the tensile strength is σ, S is the safety factor, the wall thickness is δ, and the outer diameter is D.
for example:
DN=10MM, wall thickness is 3mm, what is the maximum pressure of seamless steel welded pipe?
The tensile strength of the material is σ, the pressure is P, and the outer diameter is D;
Welded pipe wall thickness δ=(P*D)/(2*σ/S)
S is the safety factor;
Because P is less than 7 MPa, S selects S=8; P is less than 17.5 MPa, S selects S=6; P is greater than 17.5 MPa, and S selects S=4;
We choose the safety factor of S=6; the tensile strength of 20 steel is 410MPa.
Therefore, the pressure that the welded pipe can withstand
P=(2*σ/S*δ)/D
=(2*410/6*3)/(10+6)
=26.25MPa>Set 17.5MPa
Therefore, the safety factor is taken as S=4
Therefore, the pressure that the welded pipe can withstand P=(2*σ/S*δ)/D
=(2*410/4*3)/(10+6)
=39.375MPa
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